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	<title>Planet X &#187; web</title>
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	<description>2012</description>
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		<title>Planet X Reviews</title>
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		<pubDate>Wed, 07 Dec 2005 16:49:38 +0000</pubDate>
		<dc:creator>Don Allen</dc:creator>
				<category><![CDATA[Planet X]]></category>
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		<category><![CDATA[planet x reviews]]></category>
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		<description><![CDATA[ASTRONOMY QUESTIONS PLEASE HELP! I do not understand.? 1) A friend convinced you to invest your savings in an extraordinary business opportunity, a new Earth-orbiting satellites. The orbit was found to have an eccentricity e = 0.8 and a semi-major axis of 4,400 miles. Earth radius = 3954 miles. This person is still your friend? [...]]]></description>
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<b>ASTRONOMY QUESTIONS PLEASE HELP! I do not understand.?</b>
<p> <i>1) A friend convinced you to invest your savings in an</i> extraordinary business <i>opportunity,</i> a new Earth-orbiting satellites. The orbit was found to have an eccentricity e = 0.8 and a semi-major axis of 4,400 miles. Earth radius = 3954 miles. This person is still your friend? Explain and show their work. 2) a lunar orbiting satellite has a mass of 1,000 kg, an eccentricity e = 0.5 and a semi-major axis a = 6000 km. The total angular momentum MVR is 1.8 x 1010 kg km2/hr. What is the orbital velocity apolune (farthest point from the orbit of the moon)? Show your work. 3) A new planet was discovered orbiting a star whose mass is the same as that of the sun. planet&#39;s orbital period, determined from the periodic Doppler shift spectrum of the star, is known to be 16 years. What is the semi-major axis of the AU for the new planet? Show your work. Review of the theory of the third law? </p>
<p> 1) Calculate the minor semiaxis quickly shows that the satellite has an orbit that would pass through the Earth 2) The speed at r = 6000 km is v = 1.8 x 10 Km2/hr/1 ^ 10 kg, 000 kg / 3.000 km / h 6000 km distance is a apolune 1 (+ e) * 1.5 = 6000 km = 9.000 km. Therefore, the speed is 3000 km / h * 6.000 km / 9,000 km = 2.000 km due to conservation of angular momentum. 3) The version of Newton&#39;s third law of Kepler says d [AU] ^ 3 = P [years] ^ 2 * [M SolarMasses] Therefore, in this case = (16 * 1 ^ 2) ^ (1 / 3) = 6.35 AU </p>
<p><b>L4D2 Custom Map reviews: ZOMBIES FROM PLANET X!!1! Pt. 2</b><br />
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